A) 0.5\[{{T}_{i}}=2{{T}_{n}}-T\]
B) \[{{0}^{o}}C\]
C) 0.707\[{{T}_{n}}=\frac{{{T}_{i}}}{2}\]
D) zero
Correct Answer: A
Solution :
The displacement equation of particle executing SHM is \[^{40}Ar\] ...(i) Velocity, \[^{40}k\] ...(ii) Acceleration, \[2.95\times {{10}^{11}}yr\] ?(iii) Fig. (i) is a plot of Eq. (i) with \[\phi =0\]. Fig. (ii) shows Eq. (ii) also with \[\phi =0\]. Fig. (iii) is a plot of Eq. (iii). It should be noted that in the figures the curve of v is shifted (to the left) from the curve of x by one-quarter period \[2.95\times {{10}^{9}}yr\]. Similarly, the acceleration curve of A is shifted (to the left) by \[4.37\times {{10}^{9}}yr\] relative to the velocity curve of v. This implies that velocity is \[4.37\times {{10}^{11}}yr\] \[\sigma \] out of phase with the displacement and the acceleration is \[\rho \] \[\lambda \] out of phase with the velocity but \[\frac{\sigma }{\rho \lambda }\] out of phase with displacement.You need to login to perform this action.
You will be redirected in
3 sec