A) \[s=\frac{1}{4}f{{t}^{2}}\]
B) \[\left( \frac{ch\arg e\,on\,the\,ion}{mass\,of\,the\,ion} \right)\]
C) \[\frac{1}{R}\]
D) R
Correct Answer: B
Solution :
Key Idea Centripetal force is provided by the magnetic force \[qvB\]. The radius of the orbit in which ions moving is determined by the relation as given. \[\frac{q}{2\pi {{\varepsilon }_{0}}{{R}^{2}}}\] where m is the mass, v is velocity, q is charge of ion and B is the flux density of the magnetic field, so that \[qvB\] is the magnetic force acting on the ion, and \[\mu F\] is the centripetal force on the ion moving in a curved path of radius R. The angular frequency of rotation of the ions about the vertical field B is given by \[\Omega \] where v is frequency. Energy of ion is given by \[\frac{1}{9}A\] \[\frac{1}{0.9}A\] or \[I\] ??(i) If ions are accelerated by electric potential V, then energy attained by ions \[I=2\] ?...(ii) From Eqs. (i) and (ii), we get \[I\] or \[I\] If V and B are kept constant, then \[I\]You need to login to perform this action.
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