A) \[({{R}_{2}}>{{R}_{1}})\]
B) \[{{R}_{2}}\]
C) \[R=\frac{{{R}_{2}}\times ({{R}_{1}}+{{R}_{2}})}{({{R}_{2}}-{{R}_{1}})}\]
D) \[R={{R}_{2}}-{{R}_{1}}\]
Correct Answer: B
Solution :
\[\omega \] \[\beta =\frac{\alpha }{1-\alpha }=\frac{0.98}{1-0.98}=49\] \[{{A}_{v}}=(49)\left[ \frac{500\times {{10}^{3}}}{{{R}_{1}}} \right]\] According to the question, \[=6.0625\times {{10}^{6}}=49\times \left[ \frac{500\times {{10}^{3}}}{{{R}_{1}}} \right]\times 49\] \[\therefore \] \[{{R}_{1}}=198\Omega \] \[{{S}_{x}}=(6-4)\cos {{45}^{o}}\hat{i}\] \[=2\times \frac{1}{\sqrt{2}}=\sqrt{2}km\] \[{{S}_{y}}=(6+4)\sin {{45}^{o}}\hat{j}\] \[=10\times \frac{1}{\sqrt{2}}=5\sqrt{2}km\]You need to login to perform this action.
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