A) \[12\times {{10}^{-5}}\]
B) \[{{10}^{-5}}\]
C) \[5\times {{10}^{-5}}\]
D) \[7\times {{10}^{-5}}\]
Correct Answer: C
Solution :
\[\Rightarrow \] \[V=\frac{av}{A}\] \[p+\rho gh+\frac{1}{2}\rho {{v}^{2}}=p+0+\frac{1}{2}\rho {{v}^{2}}\] \[\Rightarrow \] \[{{v}^{2}}=\frac{2gh}{1-{{\left( \frac{a}{A} \right)}^{2}}}=\frac{2\times 10\times (3-0.525)}{1-{{(0.1)}^{2}}}\] \[=50{{(m/s)}^{2}}\] \[U=k|x{{|}^{3}}\] \[\Rightarrow \]You need to login to perform this action.
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