A) 198\[k\Omega \]
B) 300\[\alpha \]
C) 100\[\Omega \]
D) 400\[\Omega \]
Correct Answer: A
Solution :
Key Idea Apply the concept, power gain is product of current gain and voltage gain and find the resistance Voltage gain \[F=-\frac{dU}{dx}\] Also, current gain \[=-3k|x{{|}^{2}}\] \[x=a\sin \omega t\] Power gain \[\frac{{{d}^{2}}x}{d{{t}^{2}}}+{{\omega }^{2}}x=0\] \[\Rightarrow \] \[a=\frac{{{d}^{2}}x}{d{{t}^{2}}}=-{{\omega }^{2}}x\]You need to login to perform this action.
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