A) 10\[\Omega \]
B) 5\[\Omega \]
C) \[\frac{1}{2}\Omega \]
D) 500\[\Omega \]
Correct Answer: A
Solution :
According to Wheatstone bridge principle \[\frac{P}{Q}=\frac{R}{S}\] Let length of bridge wire is 100 cm. \[\therefore \] \[\frac{R}{S}=\frac{l}{100-l}\] Here \[R=10\Omega ,l=50cm\] \[\frac{10}{S}=\frac{50}{100-50}\] or \[S=10\Omega \]You need to login to perform this action.
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