A) 3\[\Omega \]
B) 4\[\Omega \]
C) 4.5\[\Omega \]
D) 15\[\Omega \]
Correct Answer: B
Solution :
Equivalent resistance of \[{{R}_{1}}\] and \[{{R}_{2}}\] (in parallel is given by \[R=\frac{6\times 6}{6+6}=3\Omega \] Equivalent resistance of \[{{R}_{5}}\] and \[{{R}_{7}}\] (in parallel) \[R=\frac{10\times 10}{10+10}=5\Omega \] Now, the circuit is reduced to Now, this circuit can be shown as it is balanced \[\left( \frac{5}{3}=\frac{5}{3} \right)\] Total resistance between AB \[{{R}_{AB}}=\frac{(5+3)(5+3)}{(5+3)+(5+3)}\] \[=\frac{8\times 8}{8+8}=4\Omega \]You need to login to perform this action.
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