A) \[m=\frac{wg}{g-a}\]
B) \[m=w\left( 1+\frac{a}{g} \right)\]
C) the force of friction exerted by the rope on the monkey is \[m(g-a)N\]
D) the tension in the rope is \[wg\,N\]
Correct Answer: C
Solution :
The reading of the spring balance = tension in the rope = the force of friction between rope and the monkey \[=mg-ma\,=m(g-a)\,N\]You need to login to perform this action.
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