A) 2
B) 4
C) 6
D) 8
Correct Answer: B
Solution :
Given \[s=6{{t}^{2}}-{{t}^{3}}\] Velocity \[v=\frac{ds}{dt}=12t-3{{t}^{2}}\] If velocity is zero, then \[0=12t-3{{t}^{2}}\] \[\Rightarrow \] \[t=4\,s\]You need to login to perform this action.
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