A) 14 m/s
B) 3 m/s
C) 3.92 m/s
D) 5 m/s
Correct Answer: A
Solution :
Key Idea: In a horizontal circle, tension in the string provides the necessary centripetal force. For a ball to move in horizontal circle, the ball should satisfied the condition: Tension in the string = Centripetal force \[\Rightarrow {{T}_{\max }}=\frac{M{{v}^{2}}_{\max }}{R}\] \[\Rightarrow {{v}_{\max }}=\sqrt{\frac{{{T}_{\max }}.R}{M}}....(i)\] Making substitution, we obtain \[{{v}_{\max }}=\sqrt{\frac{25\times 1.96}{0.25}}\] \[=\sqrt{196}\] \[=14\,m/s\] Note: In a vertical circle, the tension at the highest point in zero and at lowest pint is maximum.
You need to login to perform this action.
You will be redirected in
3 sec
