A) \[{{K}_{p}}={{P}_{C{{O}_{2}}}}\]
B) \[{{K}_{p}}=\frac{[MgO]\,[C{{O}_{2}}]}{[MgC{{O}_{3}}]}\]
C) \[{{K}_{p}}=\frac{{{P}_{MgO}}+{{P}_{C{{O}_{2}}}}}{{{P}_{MgC{{O}_{3}}}}}\]
D) \[{{K}_{p}}=\frac{{{P}_{MgO}}+{{P}_{C{{O}_{2}}}}}{{{P}_{MgC{{O}_{3}}}}}\]
Correct Answer: A
Solution :
In heterogeneous system \[{{K}_{c}},\,{{K}_{p}}\] is not based upon concentratrion or pressure of solid substance. Hence, at equilibrium their concentration or pressure are assumed as one \[\therefore MgC{{O}_{3}}(g)\rightleftharpoons MgO\,(s)+C{{O}_{2}}(g)\] \[{{K}_{p}}={{P}_{C{{O}_{2}}}}\]
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