A) NO
B) \[N_{2}^{+}\]
C) CO
D) \[O_{2}^{-}\]
Correct Answer: C
Solution :
Paramagnetic character is shown by those atoms or molecules which have unpaired electrons. In the given compounds CO is not paramagnetic since it does not have unpaired electrons. The configuration of CO molecule is \[CO(14)=\sigma 1{{s}^{2}},\,\sigma *\,1{{s}^{2}},\,\sigma 2{{s}^{2}},\,\sigma *\,2{{s}^{2}},\,\sigma 2p_{x}^{2},\] \[\pi 2p_{y}^{2},\,\pi 2p_{z}^{2}\]
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