A) 2
B) 3
C) 4
D) 1
Correct Answer: A
Solution :
Given, molality,\[=[{{M}^{1}}{{L}^{1}}{{T}^{-2}}]\] \[=[{{M}^{1}}{{L}^{1}}{{T}^{-2}}]\] \[\therefore \] \[\therefore \] \[\text{-}\] \[\text{-}\] \[\text{-}\] Since, the compound is ionic, so number of moles produced is equal to vant' Hoff factor, i. Hence, 2 moles of ions are produced. \[_{Z}^{A}X\xrightarrow[{}]{{}}{{\,}_{Z+}}_{1}^{A}Y+\beta _{-1}^{0}\]You need to login to perform this action.
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