A) toluene
B) chlorobenzene
C) benzylchloride
D) xylene
Correct Answer: A
Solution :
Key Idea \[{{V}_{A}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{\sigma 4\pi {{a}^{2}}}{a}-\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{\sigma 4\pi {{b}^{2}}}{b}\]in the presence of anhydrous \[+\frac{1}{4\pi {{\varepsilon }_{0}}},\frac{\sigma 4\pi {{c}^{2}}}{c}\]acts as alkylation agent and introduces an alkyl group This reaction is known as Friedel-Craft's alkylation of benzene.You need to login to perform this action.
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