NEET AIPMT SOLVED PAPER SCREENING 2011

  • question_answer
    A body is moving with velocity 30 m/s towards east. After 10 s its velocity becomes 40 m/s towards north. The average acceleration of the body is

    A) \[7\,m/{{s}^{2}}\]                           

    B)  \[\sqrt{7}\,m/{{s}^{2}}\]

    C)  \[5\,m/{{s}^{2}}\]                          

    D)  \[1\,m/{{s}^{2}}\]

    Correct Answer: C

    Solution :

    Average acceleration\[=\frac{\text{Change}\,\text{in}\,\text{velocity}}{\text{Total}\,\text{time}}\] \[a=\frac{|{{\mathbf{V}}_{f}}-{{\mathbf{v}}_{i}}|}{\Delta t}\] \[=\frac{\sqrt{{{30}^{2}}+{{40}^{2}}}}{10}=\frac{\sqrt{900+1600}}{10}\] \[=5\,\text{m}{{\text{s}}^{-2}}\]


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