A) Virtual, upright, height = 0.5 cm
B) Real, inverted, height = 4 cm
C) Real, inverted, height = 1 cm
D) Virtual, upright, height = 1 cm
Correct Answer: B
Solution :
In general we have assumed\[\mu =1.5\] So,\[f=20\,cm\] \[\frac{1}{f}=\frac{1}{v}+\frac{1}{\mu }\] \[\frac{1}{20}=\frac{1}{v}+\frac{1}{30}\] \[\frac{1}{v}=\frac{1}{20}-\frac{1}{30}=\frac{10}{600}\] \[v=60\,\text{cm}\] \[\frac{{{h}_{i}}}{{{h}_{0}}}=2\] \[{{h}_{i}}=2\times |{{h}_{0}}|\] \[{{h}_{i}}=4\,\text{cm}\] Here, image is real, inverted, magnified field and height of image is 4 cm.
You need to login to perform this action.
You will be redirected in
3 sec
