A) 300 m/s
B) 150 m/s
C) 250 m/s
D) 450 m/s
Correct Answer: A
Solution :
The standard equation of wave of amplitude a is \[y=a\sin \,(kx-\omega t)\] ... (i) where \[\omega \] is angular velocity. Given equation is \[y=0.5\,\sin \,(0.01\,\pi x-3\pi t)\] ... (ii) Comparing Eqs. (i) and (ii), we get \[k=0.01\,\pi ,\,\,\,\omega =3\,\pi \] \[k=\frac{\omega }{v}\] \[\Rightarrow \] \[v=\frac{\omega }{k}=\frac{3\pi }{0.01\,\,\pi }=300\,\,m/s\]You need to login to perform this action.
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