A) 125 Hz
B) 50 Hz
C) 200 Hz
D) 100 Hz
Correct Answer: C
Solution :
The frequency (n) of vibration of string is given by \[n=\frac{p}{2\,l}\sqrt{\frac{T}{m}}\] where T is tension, and m the mass per unit length. Given, \[p=2,\,\,\,m=5\times {{10}^{-4}}kg\], T = 20N, \[l=1\,m\] \[\therefore \] \[n=\frac{2}{2\times 1}\sqrt{\frac{20}{5\times {{10}^{-4}}}}=200\,Hz\]You need to login to perform this action.
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