A) \[767{}^\circ C\]
B) \[1040{}^\circ C\]
C) \[6500{}^\circ C\]
D) \[6227{}^\circ C\]
Correct Answer: D
Solution :
From Wiens law \[{{\lambda }_{m}}T=\] constant. \[\therefore \] \[{{\lambda }_{1}}{{T}_{1}}={{\lambda }_{2}}{{T}_{2}}\] Given, \[{{T}_{1}}={{2327}^{o}}C\] \[=2327+273=2600\,K\], \[{{\lambda }_{1}}=12000\,\overset{o}{\mathop{A}}\,\], \[{{\lambda }_{2}}=4800\,\overset{o}{\mathop{A}}\,\] \[\therefore \] \[{{T}_{2}}=\frac{12000\times 2600}{4800}=6500\,K\] In centigrade T = 6500 - 273 \[={{6227}^{o}}C\]You need to login to perform this action.
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