A) \[2\pi m\]
B) \[\sqrt{2}\pi m\]
C) \[\sqrt{{{\pi }^{2}}+4}m\]
D) \[\pi \,m\]
Correct Answer: C
Solution :
After half a revolution, vertical distance travelled by point\[=\frac{1}{2}\] times circumference of wheel\[=\pi r\]\[=\pi \] metre Total displacement of point\[=\sqrt{{{\pi }^{2}}+{{2}^{2}}}=\sqrt{{{\pi }^{2}}+4}\]You need to login to perform this action.
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