A) \[\text{2 m}/{{\text{s}}^{\text{2}}}\]
B) \[\text{2}.\text{5 m}/{{\text{s}}^{\text{2}}}\]
C) \[\text{2}.\text{7 m}/{{\text{s}}^{\text{2}}}\]
D) \[\text{4 m}/{{\text{s}}^{\text{2}}}\]
Correct Answer: C
Solution :
A body moving in circular motion, has radial \[({{a}_{R}})\] and tangential acceleration \[({{a}_{T}})\], Hence, resultant acceleration is given by \[a=\sqrt{a_{T}^{2}+a_{R}^{2}}\] Given, \[{{a}_{T}}=2m/{{s}^{2}}\], \[{{a}_{R}}=\frac{{{V}^{2}}}{r}=\frac{30\times 30}{500}=1.8\,m/{{s}^{2}}\] \[\therefore \] \[a=\sqrt{{{(1.8)}^{2}}+{{(2)}^{2}}}=\sqrt{7.24}\] \[\Rightarrow \] \[a=2.69\approx 2.7\,m/{{s}^{2}}\]You need to login to perform this action.
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