A) 50 Hz
B) 60 Hz
C) 25 Hz
D) 40 Hz
Correct Answer: A
Solution :
Capacitive reactance \[{{X}_{C}}\] is given by \[{{X}_{C}}=\frac{1}{\omega C}\] where \[\omega \] is angular frequency \[\omega =2\pi \,f\] \[{{V}_{C}}=100\,V\] \[\therefore \] \[{{X}_{C}}=\frac{1}{2\,\pi fC}\] ? (i) Also, \[{{X}_{C}}\] is given by \[{{X}_{C}}=\frac{{{V}_{C}}}{I}\] ... (ii) \[\therefore \] From Eqs. (i) and (ii), we get \[\frac{1}{2\,\pi fC}=\frac{{{V}_{C}}}{I}\] \[\Rightarrow \] \[f=\frac{I}{2\pi {{V}_{c}}C}\] Given, \[I=0.628A\], \[{{V}_{C}}=100\,V\], \[\Rightarrow \] \[f=\frac{0.628}{2\times 3.14\times 20\times {{10}^{-6}}\times 100}\] \[\Rightarrow \] \[f=50\,\,Hz\]You need to login to perform this action.
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