A) \[\frac{X-Y}{R}\]
B) \[\frac{(X-Y)R}{Y}\]
C) \[\frac{(X-Y)Y}{R}\]
D) \[(X-Y)R\]
Correct Answer: B
Solution :
Let \[I\] be the current through the circuit, then from Ohms law Given, E = X, \[\therefore \] \[I=\frac{X}{R+r}\] ... (i) The potential difference across resistor is \[{{V}_{R}}=IR\] ... (ii) Given \[{{V}_{R}}=Y\], From Eqs. (i) and (ii), we get \[Y=\frac{X\,R}{R+r}\] \[\Rightarrow \] \[Yr=(X-Y)R\] \[\Rightarrow \] \[r=\frac{(X-Y)}{Y}R\]You need to login to perform this action.
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