A) 2
B) 4
C) 8
D) 16
Correct Answer: D
Solution :
\[m=3.2\times {{10}^{-12}}g\] \[=3.2\times {{10}^{-12}}\times {{10}^{-3}}kg\] \[=3.2\times {{10}^{-15}}kg\] Potential difference = 980 V \[d=2\,cm\,=2\times {{10}^{-2}}m\] Potential difference between the plates \[V=E\times d\] or \[V=\frac{mg}{ne}\times d\] \[V=\frac{mg}{ne}\times d\] \[n=\frac{mg}{e\times v}\times d\] \[n=\frac{3.2\times {{10}^{-15}}\times 9.8\times 2\times {{10}^{-2}}}{980\times 1.6\times {{10}^{-19}}}\]\[n=4\]You need to login to perform this action.
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