A) \[8.1\times {{10}^{4}}s\]
B) \[2.7\times {{10}^{4}}s\]
C) \[9\times {{10}^{3}}s\]
D) \[3\times {{10}^{3}}s\]
Correct Answer: B
Solution :
Given, \[l=3.0\] \[A=2.0\times {{10}^{-6}}{{m}^{2}}\] \[i=30\,A\] \[{{v}_{d}}=\frac{i}{neA}\] \[{{v}_{d}}=\frac{3}{8.5\times {{10}^{28}}\times 1.6\times {{10}^{-19}}\times 2\times {{10}^{-6}}}\] \[{{v}_{d}}=1.10\times {{10}^{-4}}\] Time \[t=\frac{l}{{{v}_{d}}}=\frac{3}{1.10\times {{10}^{-4}}}\] \[2.7\times {{10}^{4}}s\]You need to login to perform this action.
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