A) \[8\pi \times {{10}^{-3}}T\]
B) \[6\pi \times {{10}^{-3}}T\]
C) \[p-n\]
D) \[3\pi \times {{10}^{-3}}T\]
Correct Answer: C
Solution :
Magnetic field \[B=\frac{{{\mu }_{0}}i}{4\pi }\frac{5N}{l}(2\pi )\] \[={{10}^{-7}}\times 8\times 5\times \frac{400\times 2\pi }{80\times {{10}^{-2}}}\] \[=4\pi \times {{10}^{-3}}T\]You need to login to perform this action.
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