A) zero
B) 0.314 J
C) 3.14 J
D) 6.28 J
Correct Answer: B
Solution :
Area \[=\pi {{r}^{2}}=\pi \times 10\times 10\times {{10}^{-4}}{{m}^{2}}\] Torque \[\tau =NiBA\,\sin \theta \] \[=20\times 5\times 0.10\times \pi \times 10\times 10\times {{10}^{-4}}\] \[=3.14\,J\]You need to login to perform this action.
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