A) 50 V
B) 100 V
C) 150 V
D) zero
Correct Answer: B
Solution :
The emf developed across the ends of the rod \[e=\frac{1}{2}B{{l}^{2}}\omega \] \[=\frac{1}{2}\times 0.5\times {{(1)}^{2}}\times 400\] = 100 VYou need to login to perform this action.
You will be redirected in
3 sec