A) 21kV
B) -21kV
C) 39 kV
D) - 39 kV
Correct Answer: C
Solution :
The electric field \[E=5\,i-3j\,kV/m\] \[E=\sqrt{25+9}\] \[=\sqrt{34}\,kV/m\] \[d=\sqrt{{{(10-4)}^{2}}+{{(3-0)}^{2}}}\] \[=\sqrt{{{(6)}^{2}}+{{(3)}^{2}}}\] \[=\sqrt{(36+9}\,=\sqrt{45}\] Potential difference between points A and B \[V=E\,.\,d\] \[=\sqrt{34}\,\times \sqrt{45}\] = 39 kVYou need to login to perform this action.
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