A) \[E=\frac{\lambda }{4\pi {{\varepsilon }_{0}}a}(-i)\]
B) \[E=\frac{\lambda }{4\pi {{\varepsilon }_{0}}a}(i)\]
C) \[E=\frac{\lambda }{2\pi {{\varepsilon }_{0}}a}(-i)\]
D) \[E=\frac{\lambda }{2\pi {{\varepsilon }_{0}}a}(i)\]
Correct Answer: C
Solution :
The electric field at the point \[x=-a\] \[{{E}_{out}}=\frac{\lambda }{2\pi {{\varepsilon }_{0}}a}\,\,(-i)\]You need to login to perform this action.
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