A) 320 W
B) 176 W
C) 144 W
D) 0
Correct Answer: A
Solution :
We have, \[{{X}_{L}}=90\,\Omega ,\,{{X}_{C}}=30\,\Omega \] and \[R={{R}_{1}}+{{R}_{2}}=44+36=80\,\Omega \] Impedance \[Z=\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}\] \[=\sqrt{{{(80)}^{2}}+{{(60)}^{2}}}\] \[Z=\sqrt{6400+3600}=100\] \[I=\frac{V}{Z}=\frac{200}{100}=2A\] \[{{P}_{av}}={{I}^{2}}R\] \[={{(2)}^{2}}\times 80=320\,\,W\]You need to login to perform this action.
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