A) \[4.54\times {{10}^{14}}Hz\]
B) \[3.5\times {{10}^{14}}Hz\]
C) \[3.5\times {{10}^{10}}Hz\]
D) \[2.5\times {{10}^{10}}Hz\]
Correct Answer: C
Solution :
The wave function\[\Psi (x,t)={{10}^{3}}\sin \pi (3\times {{10}^{6}}x-9\times {{10}^{4}}t)\] Here, Angular frequency co \[=9\times {{10}^{14}}\pi \] \[\omega =2\pi n\] \[n=\frac{\omega }{2\pi }=\frac{9\times {{10}^{14}}\pi }{2\pi }=4.5\times {{10}^{14}}Hz\]You need to login to perform this action.
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