A) \[N{{H}_{4}}Cl\] is completely dissociated in \[N{{H}_{3}}\]
B) \[N{{H}_{4}}Cl\] is partially dissociated in \[N{{H}_{3}}\]
C) \[N{{H}_{4}}Cl\] is not dissociated in \[N{{H}_{3}}\]
D) Boiling point is not raised
Correct Answer: A
Solution :
Vapour pressurs, \[\pi \propto bp\,(T)\] \[\therefore \] \[\frac{{{\pi }_{1}}}{{{\pi }_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] \[\Rightarrow \] \[\frac{760}{{{\pi }_{2}}}=\frac{240.3\,K}{306.4\,K}\] \[{{\pi }_{2}}=\frac{760\times 306.4}{240.3}=969\,torr\] \[\because {{\pi }_{2}}>{{\pi }_{1}}\] that means more gases are present or \[N{{H}_{4}}Cl\] gets completely dissociated into ammonia gas.You need to login to perform this action.
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