A) 20 min
B) 40 min
C) 56 min
D) 67 min
Correct Answer: D
Solution :
Since, the plot of the reciprocal of the concentration of A versus time is a straight line. It indicates that the given reaction is of second order. For a second order reaction, \[{{t}_{1/2}}=\frac{1}{ka}\] \[20\,\,(\min )=\frac{1}{k\times 1.0\times {{10}^{-2}}M}\] ... (i) \[{{t}_{1/2}}=\frac{1}{k\times 3.0\times {{10}^{-3}}M}\] ?. (ii) \[\frac{20}{{{t}_{1/2}}}=\frac{1\times 3.0\times {{10}^{-3}}}{1.0\times {{10}^{-2}}\times 1}=66.66\approx 67\,\min \]You need to login to perform this action.
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