A) \[{{C}_{2}}{{H}_{5}}Br\]
B) \[HO-C{{H}_{2}}C{{H}_{2}}Cl\]
C) \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}Cl\]
D) \[C{{H}_{2}}=CH-C{{H}_{2}}Cl\]
Correct Answer: B
Solution :
Grignard reagent readily reacts with compounds containing active hydrogen such as alcohols. Unsaturated halides on reaction with Grignard reagent give alkens. \[\underset{Grignard\text{ }reagent}{\mathop{C{{H}_{3}}MgCl}}\,\,\,+ClC{{H}_{2}}-CH=C{{H}_{2}}\xrightarrow{{}}\] \[\underset{but-1-ene}{\mathop{C{{H}_{3}}C{{H}_{2}}CH}}\,=C{{H}_{2}}+MgB{{r}_{2}}\]
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