A) \[\frac{q}{\pi m}\]
B) \[\frac{q}{m}\]
C) \[\frac{2q}{m}\]
D) \[\frac{q}{2m}\]
Correct Answer: D
Solution :
We know that \[L=l\omega \] \[L=2\,{{m}^{2}}\times \omega \] ?. (i) and \[m=lA\] \[=\frac{q}{T}.A\] \[=2q\times f\,\pi {{l}^{2}}\] \[=2q\times \frac{\omega }{2\,\pi }\times \pi r{{l}^{2}}\] \[=q\omega {{l}^{2}}\] ?. (ii) From Eqs. (ii) and (ii), we get \[\frac{m}{L}=\frac{q{{\omega }^{2}}}{2{{m}^{2}}\times \omega }=q/2m\]You need to login to perform this action.
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