A) 1.4 A
B) 1.2 A
C) 0.8 A
D) 0.6 A
Correct Answer: D
Solution :
Given that \[C=1.5\mu F=1.5\times {{10}^{-6}}F\] V = 60 V, \[L=15\,mH=15\times {{10}^{-3}}H\] As \[U=\frac{1}{2}C{{V}^{2}}\] and \[U=\frac{1}{2}L{{l}^{2}}\] \[\frac{1}{2}L{{l}^{2}}=\frac{1}{2}C{{V}^{2}}\] \[{{l}^{2}}=\frac{C{{V}^{2}}}{L}=\frac{1.5\times {{10}^{-6}}\times 60\times 60}{15\times {{10}^{-3}}}\] \[l=0.6\,A\]You need to login to perform this action.
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