A) 160.2
B) 150.2
C) 140.2
D) 130.2
Correct Answer: A
Solution :
\[\Delta {{T}_{f}}=\frac{{{K}_{f}}\times w\times 1000}{m\times W}\] Given, \[\Delta {{T}_{f}}={{8}^{o}}C\] \[{{K}_{f}}={{1.86}^{o}}C\,kg\,mo{{l}^{-1}}\] m = mass of solute = 35.5 + 19 = 54.5 w = 1kg \[\therefore \] \[8=\frac{1.86\times w\times 100}{54.5\times 1}\] \[W=320.5\,g\] \[KCl{{K}^{+}}+C{{l}^{-}}\,(i=2)\] Hence, \[w=\frac{w}{2}=\frac{320.5}{2}=160.2\,g\]You need to login to perform this action.
You will be redirected in
3 sec