A) \[-{{3}^{o}}C\]
B) \[-{{4}^{o}}C\]
C) \[-{{5}^{o}}C\]
D) \[-{{6}^{o}}C\]
Correct Answer: D
Solution :
\[KCl{{K}^{+}}+C{{l}^{-}}\] (2 ions) \[BaC{{l}_{2}}B{{a}^{2+}}+2C{{l}^{-}}\] (3 ions) \[\because \] 2 ions shows depression in freezing point \[=-{{4}^{o}}C\]. \[\therefore \] 3 ions shows depression in freezing point \[=\frac{-4}{2}\times 3=-{{6}^{o}}C\]You need to login to perform this action.
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