A) \[{{E}_{1}}>{{E}_{2}}>{{E}_{3}}\]
B) \[{{E}_{3}}>{{E}_{2}}>{{E}_{1}}\]
C) \[{{E}_{3}}>{{E}_{1}}>{{E}_{2}}\]
D) \[{{E}_{2}}>{{E}_{1}}>{{E}_{3}}\]
Correct Answer: D
Solution :
\[Zn+C{{u}^{2+}}\xrightarrow{{}}Z{{n}^{2+}}+Cu\]From Nernst equation, \[{{E}_{cell}}=E_{cell}^{o}-\frac{0.591}{n}\log \frac{\left[ Product \right]}{\left[ Reactant \right]}\] \[{{E}_{1}}=-\frac{0.0591}{2}\log \frac{1\,M}{1\,M}=0\] \[{{E}_{2}}=-\frac{0.0591}{2}\log \frac{0.1\,M}{1\,M}\] \[=+0.02955\] \[{{E}_{3}}=-\frac{0.0591}{2}\log \,\frac{1\,M}{0.1M}=-0.0591\] Thus, \[{{E}_{2}}>{{E}_{1}}>{{E}_{3}}\]You need to login to perform this action.
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