A) neutral
B) basic
C) acidic
D) amphoteric
Correct Answer: A
Solution :
Key Idea: Write hydrolysis reaction and then compare \[{{\text{K}}_{a}}\]and \[{{\text{K}}_{b}}\]to decide nature of resulting solution. \[\underset{\begin{smallmatrix} \text{ammonimum} \\ \,\,\,\,\,\,\,\,\text{acetate} \end{smallmatrix}}{\mathop{C{{H}_{3}}COON{{H}_{4}}}}\,+{{H}_{2}}O\underset{\text{acetic}\,\text{acid}}{\mathop{C{{H}_{3}}COOH}}\,\] \[+\,\underset{\begin{smallmatrix} \text{ammonium} \\ \text{hydroxide} \end{smallmatrix}}{\mathop{N{{H}_{4}}OH}}\,\] Given \[{{K}_{a}}\]for \[C{{H}_{3}}COOH=1.8\times {{10}^{-5}}\] \[{{K}_{b}}\]for \[N{{H}_{4}}OH=1.8\times {{10}^{-5}}\] \[\because \]value of \[{{K}_{a}}\]and \[{{K}_{b}}\]is same. \[\therefore \] solution is neutral.You need to login to perform this action.
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