A) \[{{\,}_{8}}{{O}^{17}}\]
B) \[{{\,}_{8}}{{O}^{18}}\]
C) \[{{\,}_{9}}{{F}^{7}}\]
D) \[{{\,}_{9}}{{F}^{18}}\]
Correct Answer: A
Solution :
Key Idea: (i) Sum of atomic numbers of reactants = Sum of atomic numbers of products. (ii) Sum of atomic masses of readouts = Sum of atomic masses of products. \[\underset{\text{nitrogen}}{\mathop{{{\,}_{7}}{{N}^{14}}}}\,+\,\underset{\alpha -\text{particle}}{\mathop{_{2}H{{e}^{4}}}}\,\xrightarrow{{}}{{\,}_{8}}{{O}^{17}}+\underset{\text{proton}}{\mathop{{{\,}_{1}}{{H}^{1}}}}\,\]You need to login to perform this action.
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