A) 40
B) 50
C) 60
D) 70
Correct Answer: B
Solution :
Key Idea:\[\text{Moles}\,\text{=}\,\,\frac{\text{Mass}}{\text{Molecular}\,\text{mass}}\] or Mass = Moles \[\times \] molecular mass Molecular mass of \[CaC{{O}_{3}}\] \[40+12+16\times 3=40+12+48=100\] Moles of \[CaC{{O}_{3}}=\frac{3.01\times {{10}^{23}}}{6.02\times {{10}^{23}}}=0.5\] Mass of a \[CaC{{O}_{3}}=0.5\times 100=50\,g\]You need to login to perform this action.
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