A) \[e<p<n<a\]
B) \[~n<p<e<\alpha \]
C) \[n<p<\alpha <e\]
D) \[n<\alpha <p<e\]
Correct Answer: D
Solution :
Key Idea: Find e/m (charge/mass) of all the given particles and then arrange them in given order. (i) e/m of electron \[=\frac{1.6\times {{10}^{-19}}}{9.1\times {{10}^{-28}}}=0.175\times {{10}^{9}}\] (ii) e/m of proton\[=\frac{1.6\times {{10}^{-19}}}{1.673\times {{10}^{-24}}}={{10}^{5}}\] (iii) e/m of neutron\[=\frac{0}{1.673\times {{10}^{-24}}}=0\] (iv) e/m of \[\alpha -\]particle \[=\frac{2\times 1.6\times {{10}^{-19}}}{4\times 1.67\times {{10}^{-24}}}=0.5\times {{10}^{5}}\] \[\therefore \] The correct order is \[n<\alpha <p<e\]You need to login to perform this action.
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