A) 2 A
B) 200\[\sqrt{2}\] A
C) 100\[\sqrt{2}\] A
D) 1.41 A
Correct Answer: D
Solution :
\[e=220\sin 100\,\pi t,\,\omega =1000\,\pi \] \[\Rightarrow \] \[f=\frac{\omega }{2\pi }=500\,Hz\] \[{{e}_{0}}=200\,V\] At resonance Z = R So, \[{{i}_{0}}=\frac{200}{R}=\frac{200}{100}=2A\] \[{{i}_{rms}}=\frac{{{i}_{0}}}{\sqrt{2}}=\frac{2}{\sqrt{2}}=\sqrt{2}=1.41\,A\]You need to login to perform this action.
You will be redirected in
3 sec