A) 18.89 V
B) 3 V
C) 15 V
D) 9.42 V
Correct Answer: D
Solution :
Induced emf \[e=\pi {{l}^{2}}Bn=\frac{{{l}^{2}}B\omega }{2}\] \[=\frac{{{(1.0)}^{2}}\times 0.25\times 2\times 3.14\times 12}{2}=9.42\,V\]You need to login to perform this action.
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