A) \[i\]
B) \[i-1\]
C) \[-i\]
D) 0
Correct Answer: B
Solution :
\[\sum\limits_{n=1}^{13}{({{i}^{n}}+{{i}^{n+1}})}=\sum\limits_{n=1}^{13}{{{i}^{n}}}+\sum\limits_{n=1}^{13}{{{i}^{n}}^{+1}}\] \[=i\left( \frac{1-{{i}^{13}}}{1-i} \right)+{{i}^{2}}\left( \frac{1-{{i}^{13}}}{1-i} \right)\] \[=i\frac{(1-i)}{(1-i)}-\frac{(1-i)}{(1-i)}\] \[=i-1\]You need to login to perform this action.
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