A) 0
B) \[1/2\]
C) 1
D) \[-\text{ }1\]
Correct Answer: B
Solution :
From the given relation, we have \[3{{\sin }^{-1}}x+{{\sin }^{-1}}x+{{\cos }^{-1}}x=\pi \] \[\Rightarrow \] \[3{{\sin }^{-1}}x+\frac{\pi }{2}=\pi \Rightarrow 3{{\sin }^{-1}}x=\pi /2\] \[\Rightarrow \] \[{{\sin }^{-1}}x=\pi /6\Rightarrow x=1/2\]You need to login to perform this action.
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