A) x-2=0
B) \[y-2=0\]
C) x + y - 4 = 0
D) None of these
Correct Answer: B
Solution :
Given equations of lines are \[\sqrt{3x}+y=0\]and\[\sqrt{3x}-y=0\] The slopes of the lines are \[\tan {{\theta }_{1}}=-\sqrt{3}\] and \[\tan {{\theta }_{2}}=\sqrt{3}\] \[\Rightarrow \] \[{{\theta }_{1}}={{120}^{o}}\] and \[{{\theta }_{2}}={{60}^{o}}\] Thus, the lines make angles \[\text{12}0{}^\circ \] and \[\text{6}0{}^\circ \]1o the, X-axis. Any line parallel to X-axis forms an equilateral triangle and it passes through the point (2,2). Hence, equation of required line is y=2 or y-2=0,You need to login to perform this action.
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