A) \[(3,\infty )\]
B) \[\left( \frac{1}{2},3 \right)\]
C) \[\left( -3,-\frac{1}{2} \right)\]
D) \[\left( 0,\frac{1}{2} \right)\]
Correct Answer: B
Solution :
Since, the given point \[(a,{{a}^{2}})\] lies inside the angle between two lines. Then, \[{{a}^{2}}-\frac{a}{2}>0\] and \[{{a}^{2}}-3a<0\] \[\Rightarrow \] \[a\in (-\infty ,0)\cup \left( \frac{1}{2},\infty \right)\]and \[a\in (0,3)\] \[\Rightarrow \] \[a\in \left( \frac{1}{2},3 \right)\]You need to login to perform this action.
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